Azimuth - not the correct display (?)

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Bostjan
Posts: 337
Joined: Fri Oct 17, 2008 4:06 pm

Azimuth - not the correct display (?)

Post by Bostjan » Mon Jun 03, 2019 12:54 pm

I thought that the position user data variable "Current pan angle with north $(an)" means "azimuth"...BUT if so, the script formula displays just the opposite. North is 0° and East is 90° but with $(an) it displays -90° for East and 90° for the West. the variable $(ap) is with the same result.
Example (from my 22 km trekking in 2010): at the mid/bottom of the surround photography are the info about the elevation and the azimuth (at least I want), but the "azimuth" is wrong: http://www.burger.si/PoZasavsko/360_Lit ... z/vrp.html

Bostjan
Posts: 337
Joined: Fri Oct 17, 2008 4:06 pm

Re: Azimuth - not the correct display (?)

Post by Bostjan » Mon Jun 03, 2019 9:44 pm

Ok. let's simplify the question: What does "Current pan angle with north $(an)" display?

Bostjan
Posts: 337
Joined: Fri Oct 17, 2008 4:06 pm

Re: Azimuth - not the correct display (?)

Post by Bostjan » Fri Jun 14, 2019 10:13 am

Even when we are out of geography (azimuth), the pan (+) or (-) is the same way: http://www.conitec.net/beta/aentity-pan.htm
A script bug?

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